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11065887995904,    28455140560896,    45731475901440,    47038089498624,    30238771820544,    11108120260608,     1785233613312;\n  8:  3718988421120,  43034008872960,  221317759918080,   663953279754240,  1280481325240320,  1646333132451840,  1411142684958720,   777568418242560,   249932705863680,   35704672266240;\n  9: 57272421685248, 736359707381760, 4260366878423040, 14606972154593280, 32865687347834880, 50707060479516672, 54328993370910720, 39915178803118080, 19244818351503360, 5498519529000960, 706952510871552;\n","recurrence_sentence":"The row polynomials satisfy (n+1)*P(n,x) = (14*n+28+(18*n+36)*x)*P(n-1,x) for n >= 1, with P(0,x) = 504 + 648*x.","mathematica":"P[0, x_] := 504 + 648*x;\nP[n_, x_] := P[n, x] = Expand[Together[((14*n + 28 + (18*n + 36)*x)*P[n - 1, x])/(n + 1)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 504 + 648*x; for(n = 1, N, my(i = n + 1); v[i] = ((14*n + 28 + (18*n + 36)*x)*v[i - 1])/(n + 1)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-c11cb6bca0e3e7dc","steps":["basis A013610","D"],"edges":["e-89b2e37c644537dd","e-432da6ddf975cd40"],"text":"A038284 \u2192 basis A013610 \u2192 D"},"headline":"A038284 \u2192 basis A013610 \u2192 D","chain":null}