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2,    4;\n  2:   4,   16,    12;\n  3:   8,   48,    72,     32;\n  4:  16,  128,   288,    256,     80;\n  5:  32,  320,   960,   1280,    800,    192;\n  6:  64,  768,  2880,   5120,   4800,   2304,    448;\n  7: 128, 1792,  8064,  17920,  22400,  16128,   6272,   1024;\n  8: 256, 4096, 21504,  57344,  89600,  86016,  50176,  16384,  2304;\n  9: 512, 9216, 55296, 172032, 322560, 387072, 301056, 147456, 41472, 5120;\n","recurrence_sentence":"The row polynomials satisfy (1+n*x)*P(n,x) = (2+(2*n+4)*x+(2*n+2)*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((2 + (2*n + 4)*x + (2*n + 2)*x^2)*P[n - 1, x])/(1 + n*x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((2 + (2*n + 4)*x + (2*n + 2)*x^2)*v[i - 1])/(1 + n*x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-d28ad9841fc73317","steps":["\u03b8+1"],"edges":["e-0211c2ba010af36a"],"text":"A038208 \u2192 \u03b8+1"},"headline":"A038208 \u2192 \u03b8+1","chain":null}