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Branden, arXiv:1410.6601: sum_k f(k) x^k / k! = f(theta) e^x = C e^x x^m prod (1 + x/a_j), a_j > 0); f(k) has one sign for k >= 0, so coefficients of one sign stay of one sign; applied to f(n, .) for each n","lean_route":null,"lean_declarations":["RealRooted.isMultiplierSequence_eval_of_roots_nonpos","RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos","RealRooted.isMultiplierSequence_iff_preserves"],"certificate_hash":"1aaf7ad354736677e4bce12bec582183eb4e7b350cd08f1553e51566223ee7a5","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},{"claim":"interlacing","from_index":1,"kind":"weak","orientation":"unordered"}],"premises":[{"position":0,"node_id":"n-e88ccd05662b8cd9","role":"sequence","name":"basis_map_A013609 of Triangle whose (i,j)-th entry is binomial(i,j)*12^(i-j)*1^j.","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:           1;\n  1:          13,           4;\n  2:         169,         104,          12;\n  3:        2197,        2028,         468,          32;\n  4:       28561,       35152,       12168,        1664,         80;\n  5:      371293,      571220,      263640,       54080,       5200,       192;\n  6:     4826809,     8911032,     5140980,     1406080,     202800,     14976,      448;\n  7:    62748517,   135150652,    93565836,    31988320,    6151600,    681408,    40768,    1024;\n  8:   815730721,  2007952544,  1621807824,   665357056,  159941600,  23622144,  2119936,  106496,   2304;\n  9: 10604499373, 29366305956, 27107359344, 12974462592, 3742633440, 690947712, 82677504, 6230016, 269568, 5120;\n","recurrence_sentence":"The row polynomials satisfy (13+2*n*x)*P(n,x) = (169+(26*n+52)*x+(4*n+4)*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((169 + (26*n + 52)*x + (4*n + 4)*x^2)*P[n - 1, x])/(13 + 2*n*x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((169 + (26*n + 52)*x + (4*n + 4)*x^2)*v[i - 1])/(13 + 2*n*x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-81e6fb4f9f226d77","steps":["basis A013609","\u03b8+1"],"edges":["e-ec56a67a9fb88114","e-928b6d155dc3e792"],"text":"A038327 \u2192 basis A013609 \u2192 \u03b8+1"},"headline":"A038327 \u2192 basis A013609 \u2192 \u03b8+1","chain":null}
