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    78364164096;\n  6:     1099511627776,      9895604649984,      38963943309312,      87668872445952,      123284351877120,      110955916689408,       62412703137792,       20061226008576,        2821109907456;\n  7:    35184372088832,    356241767399424,    1603087953297408,    4208105877405696,     7101178668122112,     7988826001637376,     5991619501228032,     2888816545234944,      812479653347328,     101559956668416;\n  8:  1125899906842624,  12666373951979520,   64123518131896320,  192370554395688960,   378729528966512640,   511284864104792064,   479329560098242560,   308140431491727360,   129996744535572480,   32499186133893120,    3656158440062976;\n  9: 36028797018963968, 445856363109679104, 2507942042491944960, 8464304393410314240, 19044684885173207040, 29995378694147801088, 33744801030916276224, 27116357971272007680, 15252951358840504320, 5719856759565189120, 1286967770902167552, 131621703842267136;\n","recurrence_sentence":"The row polynomials satisfy P(n,x) = (32+36*x)*P(n-1,x) for n >= 1, with P(0,x) = 1024 + 2304*x + 1296*x^2.","mathematica":"P[0, x_] := 1024 + 2304*x + 1296*x^2;\nP[n_, x_] := P[n, x] = Expand[(32 + 36*x)*P[n - 1, x]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1024 + 2304*x + 1296*x^2; for(n = 1, N, my(i = n + 1); v[i] = (32 + 36*x)*v[i - 1]); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-c11cb6bca0e3e7dc","steps":["basis A013610","basis A013609"],"edges":["e-89b2e37c644537dd","e-478b8a312a0ccb5d"],"text":"A038284 \u2192 basis A013610 \u2192 basis A013609"},"headline":"A038284 \u2192 basis A013610 \u2192 basis A013609","chain":null}