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2233540046080,         798371761152,         158541910016,          13492928512;\n  6:      23811286661761,      113483578983712,      236625334902208,      281936569245184,       209952764331520,      100062594064384,       29805879083008,        5073341120512,        377801998336;\n  7:    1119130473102767,     6000444238763772,    14298930951947712,    19876528131785472,     17762003862446592,    10581619322308608,     4202628950704128,     1073011646988288,     159810245296128,      10578455953408;\n  8:   52599132235830049,   313356532468774760,   840062193426928080,  1334566888848453120,   1391356969224983040,   994672216297009152,   493808901707735040,   168105158028165120,   37555407644590080,    4971874298101760,    296196766695424;\n  9: 2472159215084012303, 16200532728635655092, 48256906000191313040, 86246385191831282880, 102761650441330890240, 85707589304258955264, 51059840436579803136, 21727591675140341760, 6472048584084357120, 1285229506059304960, 153133728381534208, 8293509467471872;\n","recurrence_sentence":"The row polynomials satisfy P(n,x) = (47+28*x)*P(n-1,x) for n >= 1, with P(0,x) = 2209 + 2632*x + 784*x^2.","mathematica":"P[0, x_] := 2209 + 2632*x + 784*x^2;\nP[n_, x_] := P[n, x] = Expand[(47 + 28*x)*P[n - 1, x]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 2209 + 2632*x + 784*x^2; for(n = 1, N, my(i = n + 1); v[i] = (47 + 28*x)*v[i - 1]); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-5cf6acfdac607d6d","steps":["basis A013611","x \u21a6 x+1"],"edges":["e-0d83dd77e9f6bf78","e-9a8f3c7bf4c2d52c"],"text":"A038333 \u2192 basis A013611 \u2192 x \u21a6 x+1"},"headline":"A038333 \u2192 basis A013611 \u2192 x \u21a6 x+1","chain":null}
