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v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (1 + 3*x)*v[i - 1]); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}},{"oeis_id":"A013610","target":"triangle","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":true,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0: 1;\n  1: 1,  3;\n  2: 1,  6,   9;\n  3: 1,  9,  27,   27;\n  4: 1, 12,  54,  108,    81;\n  5: 1, 15,  90,  270,   405,   243;\n  6: 1, 18, 135,  540,  1215,  1458,   729;\n  7: 1, 21, 189,  945,  2835,  5103,  5103,  2187;\n  8: 1, 24, 252, 1512,  5670, 13608, 20412, 17496,  6561;\n  9: 1, 27, 324, 2268, 10206, 30618, 61236, 78732, 59049, 19683;\n","recurrence_sentence":"The row polynomials satisfy P(n,x) = (1+3*x)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[(1 + 3*x)*P[n - 1, x]];\nTable[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (1 + 3*x)*v[i - 1]); v};\nrow(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":true}},{"oeis_id":"A027465","target":"reversed_triangle","first_row":0,"oeis_offset":0,"reversed":true,"trim_zeros":"none","regular_triangle":true,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:     1;\n  1:     3,     1;\n  2:     9,     6,     1;\n  3:    27,    27,     9,     1;\n  4:    81,   108,    54,    12,     1;\n  5:   243,   405,   270,    90,    15,     1;\n  6:   729,  1458,  1215,   540,   135,    18,    1;\n  7:  2187,  5103,  5103,  2835,   945,   189,   21,   1;\n  8:  6561, 17496, 20412, 13608,  5670,  1512,  252,  24,  1;\n  9: 19683, 59049, 78732, 61236, 30618, 10206, 2268, 324, 27, 1;\n","recurrence_sentence":"Row n lists the coefficients of P(n,x) in descending powers of x, where P(n,x) = (1+3*x)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[(1 + 3*x)*P[n - 1, x]];\nTable[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (1 + 3*x)*v[i - 1]); v};\nrow(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":true,"trim_zeros":"none","regular_triangle":true}}],"derivation":{"root":"n-6a5af5e1168bb679","steps":[],"edges":[],"text":"A013610"},"headline":"A013610: Triangle of coefficients in expansion of (1+3*x)^n.","chain":null}
