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      439006988288;\n  7:    5068800000000,    44605440000000,    171730944000000,    377808076800000,    519486105600000,     457147772928000,    251431275110400,     79021257891840,     10865422960128;\n  8:  112640000000000,  1115136000000000,   4906598400000000,  12593602560000000,  20779444224000000,   22857388646400000,  16762085007360000,   7902125789184000,   2173084592025600,   265599227914240;\n  9: 2478080000000000, 27258880000000000, 134931456000000000, 395798937600000000, 761912954880000000, 1005725100441600000, 921914675404800000, 579489224540160000, 239039305122816000, 58431830141132800, 6427501315524608;\n","recurrence_sentence":"The row polynomials satisfy (n+1)*P(n,x) = (20*n+40+(22*n+44)*x)*P(n-1,x) for n >= 1, with P(0,x) = 880 + 968*x.","mathematica":"P[0, x_] := 880 + 968*x;\nP[n_, x_] := P[n, x] = Expand[Together[((20*n + 40 + (22*n + 44)*x)*P[n - 1, x])/(n + 1)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 880 + 968*x; for(n = 1, N, my(i = n + 1); v[i] = ((20*n + 40 + (22*n + 44)*x)*v[i - 1])/(n + 1)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-cfc5b48d32898a3e","steps":["basis A013609","D"],"edges":["e-21c2803b3d0372c9","e-0fca4daed101d063"],"text":"A038301 \u2192 basis A013609 \u2192 D"},"headline":"A038301 \u2192 basis A013609 \u2192 D","chain":null}