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Branden, arXiv:1410.6601: sum_k f(k) x^k / k! = f(theta) e^x = C e^x x^m prod (1 + x/a_j), a_j > 0); f(k) has one sign for k >= 0, so coefficients of one sign stay of one sign; applied to f(n, .) for each n","lean_route":null,"lean_declarations":["RealRooted.isMultiplierSequence_eval_of_roots_nonpos","RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos","RealRooted.isMultiplierSequence_iff_preserves"],"certificate_hash":"f100957c4b10f1b605cd228629894310a5f3afa0a37921df2c01e0f19d80fbb3","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},{"claim":"interlacing","from_index":1,"kind":"weak","orientation":"unordered"}],"premises":[{"position":0,"node_id":"n-522def1e8ebf49cd","role":"sequence","name":"Triangle of coefficients of polynomials u(n,x) jointly generated with A112351; see the Formula section.","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0: 1;\n  1: 1,   4;\n  2: 1,  16,    9;\n  3: 1,  28,   81,    16;\n  4: 1,  40,  234,   256,    25;\n  5: 1,  52,  468,  1120,   625,     36;\n  6: 1,  64,  783,  3040,  3875,   1296,     49;\n  7: 1,  76, 1179,  6448, 13825,  10836,   2401,    64;\n  8: 1,  88, 1656, 11776, 36550,  49392,  26068,  4096,   81;\n  9: 1, 100, 2214, 19456, 80150, 160056, 148176, 56064, 6561, 100;\n","recurrence_sentence":"The row polynomials satisfy (n^2+(9*n^3-9*n^2+2*n+3)*x+(9*n^4-44*n^3+61*n^2+15*n)*x^2-(48*n^4-80*n^3+114*n^2-152*n-3)*x^3+(64*n^4-128*n^3+88*n-12)*x^4)*P(n,x) = ((n^2+2*n+1)*x+(9*n^3+17*n^2+9*n+4)*x^2+(9*n^4-17*n^3-35*n^2+30*n+36)*x^3-(57*n^4+104*n^3+145*n^2+69*n-32)*x^4+(112*n^4+240*n^3+162*n^2-12*n-61)*x^5-(64*n^4+128*n^3-40*n+12)*x^6)*P(n-2,x) + (n^2+(9*n^3+2*n^2+2)*x+(9*n^4-8*n^3+17*n^2+54*n+44)*x^2-(30*n^4+68*n^3-68*n^2-272*n-210)*x^3-(32*n^4+32*n^3+436*n^2-292*n-676)*x^4+(128*n^4-384*n^2+48*n+256)*x^5)*P(n-1,x) for n >= 2, with P(0,x) = 1, P(1,x) = 1 + 4*x.","mathematica":"P[0, x_] := 1;\nP[1, x_] := 1 + 4*x;\nP[n_, x_] := P[n, x] = Expand[Together[(((n^2 + 2*n + 1)*x + (9*n^3 + 17*n^2 + 9*n + 4)*x^2 + (9*n^4 - 17*n^3 - 35*n^2 + 30*n + 36)*x^3 - (57*n^4 + 104*n^3 + 145*n^2 + 69*n - 32)*x^4 + (112*n^4 + 240*n^3 + 162*n^2 - 12*n - 61)*x^5 - (64*n^4 + 128*n^3 - 40*n + 12)*x^6)*P[n - 2, x] + (n^2 + (9*n^3 + 2*n^2 + 2)*x + (9*n^4 - 8*n^3 + 17*n^2 + 54*n + 44)*x^2 - (30*n^4 + 68*n^3 - 68*n^2 - 272*n - 210)*x^3 - (32*n^4 + 32*n^3 + 436*n^2 - 292*n - 676)*x^4 + (128*n^4 - 384*n^2 + 48*n + 256)*x^5)*P[n - 1, x])/(n^2 + (9*n^3 - 9*n^2 + 2*n + 3)*x + (9*n^4 - 44*n^3 + 61*n^2 + 15*n)*x^2 - (48*n^4 - 80*n^3 + 114*n^2 - 152*n - 3)*x^3 + (64*n^4 - 128*n^3 + 88*n - 12)*x^4)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1 + 4*x; for(n = 2, N, my(i = n + 1); v[i] = (((n^2 + 2*n + 1)*x + (9*n^3 + 17*n^2 + 9*n + 4)*x^2 + (9*n^4 - 17*n^3 - 35*n^2 + 30*n + 36)*x^3 - (57*n^4 + 104*n^3 + 145*n^2 + 69*n - 32)*x^4 + (112*n^4 + 240*n^3 + 162*n^2 - 12*n - 61)*x^5 - (64*n^4 + 128*n^3 - 40*n + 12)*x^6)*v[i - 2] + (n^2 + (9*n^3 + 2*n^2 + 2)*x + (9*n^4 - 8*n^3 + 17*n^2 + 54*n + 44)*x^2 - (30*n^4 + 68*n^3 - 68*n^2 - 272*n - 210)*x^3 - (32*n^4 + 32*n^3 + 436*n^2 - 292*n - 676)*x^4 + (128*n^4 - 384*n^2 + 48*n + 256)*x^5)*v[i - 1])/(n^2 + (9*n^3 - 9*n^2 + 2*n + 3)*x + (9*n^4 - 44*n^3 + 61*n^2 + 15*n)*x^2 - (48*n^4 - 80*n^3 + 114*n^2 - 152*n - 3)*x^3 + (64*n^4 - 128*n^3 + 88*n - 12)*x^4)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-522def1e8ebf49cd","steps":["(\u03b8+1)\u00b2"],"edges":["e-0804d81549fd7d23"],"text":"A209414 \u2192 (\u03b8+1)\u00b2"},"headline":"A209414 \u2192 (\u03b8+1)\u00b2","chain":null}
