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32212254720;\n  8:  277136640,  5912248320,  55180984320,  294298583040,   980995276800,  2092789923840,  2790386565120,  2126008811520,   708669603840;\n  9: 2217093120, 53210234880, 567575838720, 3531582996480, 14126331985920, 37670218629120, 66969277562880, 76536317214720, 51024211476480, 15118284881920;\n","recurrence_sentence":"The row polynomials satisfy n*P(n,x) = (6*n+18+(16*n+48)*x)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((6*n + 18 + (16*n + 48)*x)*P[n - 1, x])/(n)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((6*n + 18 + (16*n + 48)*x)*v[i - 1])/(n)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-a820c1859f68e71c","steps":["basis A013611","basis A013611"],"edges":["e-159425c642d412bb","e-c3cc5ae62ece989b"],"text":"A178820 \u2192 basis A013611 \u2192 basis A013611"},"headline":"A178820 \u2192 basis A013611 \u2192 basis A013611","chain":null}
