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6692600217600000000, 25964410306560000000, 69242649339494400000, 128732812856524800000, 165207109832540160000, 140931779408166912000, 73432874533729075200, 19146942100646395904, 1196683881290399744;\n","recurrence_sentence":"The row polynomials satisfy (11*n+16+11*x)*P(n,x) = (220*n+540+(484*n+1408)*x+484*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 2160 + 5632*x + 1936*x^2.","mathematica":"P[0, x_] := 2160 + 5632*x + 1936*x^2;\nP[n_, x_] := P[n, x] = Expand[Together[((220*n + 540 + (484*n + 1408)*x + 484*x^2)*P[n - 1, x])/(11*n + 16 + 11*x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 2160 + 5632*x + 1936*x^2; for(n = 1, N, my(i = n + 1); v[i] = ((220*n + 540 + (484*n + 1408)*x + 484*x^2)*v[i - 1])/(11*n + 16 + 11*x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-cfc5b48d32898a3e","steps":["basis A013611","D+1"],"edges":["e-9ac6ce8d07a161c9","e-1be3de9db1110d0e"],"text":"A038301 \u2192 basis A013611 \u2192 D+1"},"headline":"A038301 \u2192 basis A013611 \u2192 D+1","chain":null}
