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2641807540224;\n  8:  5247905883136,   81463555891200,   562857512878080,  2273288595701760,   5920542826168320,  10329366579904512,  12113329677926400,   9277147478753280,   4299541771714560,   1003886865285120,    63403380965376;\n  9: 80412794083328, 1385447153147904, 10753189377638400, 49531461133271040, 150037047316316160, 312604661221687296, 454492129515798528, 456845576424652800, 306145866798858240, 126119891970293760, 26502613243527168, 1521681143169024;\n","recurrence_sentence":"The row polynomials satisfy (12*n+19+12*x)*P(n,x) = (168*n+434+(288*n+912)*x+288*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 868 + 1824*x + 576*x^2.","mathematica":"P[0, x_] := 868 + 1824*x + 576*x^2;\nP[n_, x_] := P[n, x] = Expand[Together[((168*n + 434 + (288*n + 912)*x + 288*x^2)*P[n - 1, x])/(12*n + 19 + 12*x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 868 + 1824*x + 576*x^2; for(n = 1, N, my(i = n + 1); v[i] = ((168*n + 434 + (288*n + 912)*x + 288*x^2)*v[i - 1])/(12*n + 19 + 12*x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-c11cb6bca0e3e7dc","steps":["basis A013611","D+1"],"edges":["e-06104b6211fa5aaa","e-08bb58e872dfb747"],"text":"A038284 \u2192 basis A013611 \u2192 D+1"},"headline":"A038284 \u2192 basis A013611 \u2192 D+1","chain":null}