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Branden, arXiv:1410.6601: sum_k f(k) x^k / k! = f(theta) e^x = C e^x x^m prod (1 + x/a_j), a_j > 0); f(k) has one sign for k >= 0, so coefficients of one sign stay of one sign; applied to f(n, .) for each n","lean_route":null,"lean_declarations":["RealRooted.isMultiplierSequence_eval_of_roots_nonpos","RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos","RealRooted.isMultiplierSequence_iff_preserves"],"certificate_hash":"bf7e94765f059ce00cf0207ff1f9ebfb3b687dd5d0ecb4d4e3d1274b67a595f2","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},{"claim":"interlacing","from_index":1,"kind":"weak","orientation":"unordered"}],"premises":[{"position":0,"node_id":"n-b1e393c17b0898c2","role":"sequence","name":"Triangle of coefficients in expansion of (1+11x)^n.","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0: 1,  88,  1089;\n  1: 1, 132,  3267,   21296;\n  2: 1, 176,  6534,   85184,    366025;\n  3: 1, 220, 10890,  212960,   1830125,    5797836;\n  4: 1, 264, 16335,  425920,   5490375,   34787016,    86806489;\n  5: 1, 308, 22869,  745360,  12810875,  121754556,   607645423,   1247178944;\n  6: 1, 352, 30492, 1192576,  25621750,  324678816,  2430581692,   9977431552,   17363069361;\n  7: 1, 396, 39204, 1788864,  46119150,  730527336,  7291745076,  44898441984,  156267624249,   235794769100;\n  8: 1, 440, 49005, 2555520,  76865250, 1461054672, 18229362690, 149661473280,  781338121245,  2357947691000,  3138428376721;\n  9: 1, 484, 59895, 3513840, 120788250, 2678600232, 40104597918, 411569051520, 2864906444565, 12968712300500, 34522712143931, 41084880567984;\n","recurrence_sentence":"The row polynomials satisfy (1+(33*n+55)*x+(121*n^2+484*n+484)*x^2)*P(n,x) = (1+(33*n+99)*x+(121*n^2+1089*n+2057)*x^2+(1331*n^2+7986*n+11979)*x^3)*P(n-1,x) for n >= 1, with P(0,x) = 1 + 88*x + 1089*x^2.","mathematica":"P[0, x_] := 1 + 88*x + 1089*x^2;\nP[n_, x_] := P[n, x] = Expand[Together[((1 + (33*n + 99)*x + (121*n^2 + 1089*n + 2057)*x^2 + (1331*n^2 + 7986*n + 11979)*x^3)*P[n - 1, x])/(1 + (33*n + 55)*x + (121*n^2 + 484*n + 484)*x^2)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1 + 88*x + 1089*x^2; for(n = 1, N, my(i = n + 1); v[i] = ((1 + (33*n + 99)*x + (121*n^2 + 1089*n + 2057)*x^2 + (1331*n^2 + 7986*n + 11979)*x^3)*v[i - 1])/(1 + (33*n + 55)*x + (121*n^2 + 484*n + 484)*x^2)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-b1e393c17b0898c2","steps":["(\u03b8+1)\u00b2"],"edges":["e-51d34a8717193b90"],"text":"A013618 \u2192 (\u03b8+1)\u00b2"},"headline":"A013618 \u2192 (\u03b8+1)\u00b2","chain":null}
