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19887120,       2405700,        96228;\n   8:   33515625,    866162583,    3297077784,     3801320523,     1739187450,     350269920,     30648618,      938223;\n   9:  558593750,  23432825130,  129554477910,   210365735580,   136567160730,   40743202500,   5852426580,   387798840,    9382230;\n  10: 9496093750, 643070499786, 5084352290160, 11334864688290, 10039312393110, 4163522809446, 873240424056, 93976168572, 4880636046, 95698746;\n","recurrence_sentence":"The row polynomials satisfy n*P(n,x) = (20*n-30+(12*n-18)*x)*P(n-1,x) + (12*n-18)*x*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.","mathematica":"P[1, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((20*n - 30 + (12*n - 18)*x)*P[n - 1, x] + (12*n - 18)*x*D[P[n - 1, x], x])/(n)]];\nTable[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten","pari":"P(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((20*n - 30 + (12*n - 18)*x)*v[i - 1] + (12*n - 18)*x*deriv(v[i - 1], x))/(n)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};\nT(10)","reading":{"first_row":1,"offset":1,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-a98fae1bf9eeb913","steps":["basis A013610","basis A008277"],"edges":["e-13e67b7b83b67a66","e-139d8f99d56fba67"],"text":"A085880 \u2192 basis A013610 \u2192 basis A008277"},"headline":"A085880 \u2192 basis A013610 \u2192 basis A008277","chain":null}
