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1870768416,    14285867904,     46753749504,     85006817280,      92734709760,      60699082752,      22072393728,      3439853568;\n  7:   23150759148,   202042988928,    771436866816,   1683134982144,    2295184066560,    2003069730816,    1092583489536,    340545503232,     46438023168;\n  8:  282953722920,  2778091097760,  12122579335680,  30857474672640,   50494049464320,   55084417597440,   40061394616320,  18730002677760,   5108182548480,   619173642240;\n  9: 3423740047332, 37349891425440, 183354012452160, 533393490769920, 1018296664197120, 1333042905858048, 1211857187143680, 755443441336320, 309045044183040, 74920010711040, 8173092077568;\n","recurrence_sentence":"The row polynomials satisfy (n+1)*P(n,x) = (11*n+22+(12*n+24)*x)*P(n-1,x) for n >= 1, with P(0,x) = 264 + 288*x.","mathematica":"P[0, x_] := 264 + 288*x;\nP[n_, x_] := P[n, x] = Expand[Together[((11*n + 22 + (12*n + 24)*x)*P[n - 1, x])/(n + 1)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 264 + 288*x; for(n = 1, N, my(i = n + 1); v[i] = ((11*n + 22 + (12*n + 24)*x)*v[i - 1])/(n + 1)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-108b34f10b7468f4","steps":["basis A013611","D"],"edges":["e-8f18b93eb5dfe7b3","e-bcc8b3cdbab80436"],"text":"A038281 \u2192 basis A013611 \u2192 D"},"headline":"A038281 \u2192 basis A013611 \u2192 D","chain":null}