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remainder is removed by row annihilators of the shifted parent"],"parent_proof":{"attempts":[{"detail":"the leader is not a nonzero constant","route":"periodic_product","success":false,"variant":"P_(n+k) = c(x) P_n"},{"detail":"not applicable: expected one nonzero lag term","route":"product_recurrence","success":false,"variant":"product_recurrence"},{"detail":"no theorem matched (weighted_renewal_window: LHS must be a nonzero constant; fixed_delay_predecessor_window: LHS must be a nonzero constant)","route":"paper_theorem","success":false,"variant":"match_recurrence_theorems"},{"detail":"not applicable: the rule is not f(n) P_n = c_1(n, x) P_(n-1) + c_2(n, x) P_(n-2) with both terms nonzero","route":"three_term_recurrence","success":false,"variant":"three_term_recurrence"},{"detail":"not applicable: the rule is not f(n) P_n = c_0(n, x) P_(n-1) + c_1(n, x) P'_(n-1)","route":"liu_wang","success":false,"variant":"liu_wang"},{"detail":"HypothesisFailed: P_n = A_n(x) P_(n-1) + V_n(x) P'_(n-1) + W_n(x) P_(n-2) for n >= 3, with A_n(x) = ((-n^2 + 7 n + 20)/(n^2 + 6 n + 5)) + ((8 n^2 + 28 n + 20)/(n^2 + 6 n + 5)) x, V_n(x) = ((9 n + 21)/(n^2 + 6 n + 5)) x + ((-9 n - 21)/(n^2 + 6 n + 5)) x^2, W_n(x) = ((2 n^2 + 8 n + 6)/(n^2 + 6 n + 5)) + ((4 n^2 + 16 n + 12)/(n^2 + 6 n + 5)) x + ((2 n^2 + 8 n + 6)/(n^2 + 6 n + 5)) x^2; open hypotheses: derivative_degree_step_nonnegative: fails at n = 10: lambda_n = (-n^2 + 7 n + 20)/(n^2 + 6 n + 5) = -2/33 there (exact); multipliers_vanish_at_zero: [x^0] c_2(n, x) = 2/5 n^2 + 8/5 n + 6/5 is not the zero polynomial; constant_term_positive: fails at n = 10: A_n(0) = (-n^2 + 7 n + 20)/(n^2 + 6 n + 5) = -2/33 there (exact); lag_coefficient_nonpositive: W_n is not separable with a factor of one sign on (-inf, 0), and the sufficient monomial test (-1)^k [x^k] W_n <= 0 fails for k = 0 (not a disproof): fails at n = 3: [x^0] W_n = 3/2 there (exact)","route":"liu_wang_derivative_lag","success":false,"variant":"liu_wang_derivative_lag"},{"detail":"not applicable: the rule is not f(n) P_n = c_0(n, x) P_(n-1) + gamma(n) (x - L)(x - U) P'_(n-1)","route":"ma_wang_interval","success":false,"variant":"ma_wang_interval"},{"detail":"Unresolved: P_n = A_n(x) P_(n-1) + V_n(x) P'_(n-1) + B_n(x) P_(n-2) for n >= 3, with A_n(x) = ((-n^2 + 7 n + 20)/(n^2 + 6 n + 5)) + ((8 n^2 + 28 n + 20)/(n^2 + 6 n + 5)) x, V_n(x) = ((9 n + 21)/(n^2 + 6 n + 5)) x + ((-9 n - 21)/(n^2 + 6 n + 5)) x^2, B_n(x) = ((2 n^2 + 8 n + 6)/(n^2 + 6 n + 5)) + ((4 n^2 + 16 n + 12)/(n^2 + 6 n + 5)) x + ((2 n^2 + 8 n + 6)/(n^2 + 6 n + 5)) x^2; open hypotheses: degree_law: l_n = ([x^1] A_n + deg P_(n-1) [x^2] V_n) l_(n-1) + ([x^2] B_n) l_(n-2) when deg P_(n-1) - deg P_(n-2) = 1 (then deg P_n - deg P_(n-1) = 1): neither nonnegative step coefficients (fails at n = 10: s_n = -2/33 there (exact); t_n >= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of t_n at n = 3 + u have one sign); s_n + t_n > 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of s_n + t_n at n = 3 + u have one sign)) nor t_n <= 0 for a positive-ratio induction (fails at n = 4: t_n = 14/9 there (exact)) (not a disproof); lag_coefficient_nonpositive: neither everywhere (the quadratic test p_2 <= 0, p_0 <= 0, p_1^2 <= 4 p_2 p_0 does not hold for every n (not a disproof): fails at n = 3: p_2 = [x^2] B_n = 3/2 there (exact); fails at n = 3: p_0 = [x^0] B_n = 3/2 there (exact); p_1^2 - 4 p_2 p_0 <= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of p_1^2 - 4 p_2 p_0 at n = 3 + u have one sign)) nor on x <= 0 (B_n is not separable with a factor of one sign on (-inf, 0), and the sufficient monomial test (-1)^k [x^k] B_n <= 0 fails for k = 0 (not a disproof): fails at n = 3: [x^0] B_n = 3/2 there (exact)); root_location: constant_terms_positive: neither nonnegative step coefficients (fails at n = 10: s_n = -2/33 there (exact); t_n >= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of t_n at n = 3 + u have one sign); s_n + t_n > 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of s_n + t_n at n = 3 + u have one sign)) nor t_n <= 0 for a positive-ratio induction (fails at n = 4: t_n = 14/9 there (exact)) (not a disproof); nonnegative_coefficients: fails at n = 10: [x^0] A_n = -2/33 there (exact); [x^1] A_n >= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of [x^1] A_n at n = 3 + u have one sign); [x^0] B_n >= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of [x^0] B_n at n = 3 + u have one sign); [x^1] B_n >= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of [x^1] B_n at n = 3 + u have one sign); [x^2] B_n >= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of [x^2] B_n at n = 3 + u have one sign); [x^1] V_n >= 0 for every integer n in [3, +inf) (exact; Taylor shift: the coefficients of [x^1] V_n at n = 3 + u have one sign); fails at n = 3: [x^2] V_n = -3/2 there (exact)","route":"liu_wang_three_term","success":false,"variant":"liu_wang_three_term"},{"detail":"row relation p(n, k) [x^k] P_n + q(n, k) [x^(k-1)] P_n = 0, n >= 1, with p = (-1) (k) (k + 1) (k + 2), q = (-1) (k - n - 4) (k - n - 3) (k - n - 2); valuation v(n) = 0, degree d(n) = n + 1: every P_n, n >= 1, is nonzero and real-rooted with every root in (-inf, 0): for n >= 1 the coefficients U_j (U_j = [x^(j + v(n))] P_n, v(n) = 0) satisfy U_j = U_0(n) prod_(t <= j) R(n, t), R(n, j) = (-1) (j - n - 4) (j - n - 3) (j - n - 2) / ((j) (j + 1) (j + 2)), so sum_j U_j y^j is U_0(n) times the image of (1 + y)^(n + 1) under a nonnegative multiplier sequence, and U_0(n) != 0 for n >= 1 by its scalar recurrence","route":"hypergeometric_row","success":true,"variant":"hypergeometric_row"}],"conditional_on":[],"route":"hypergeometric_row","rows_checked":10,"statement":"every parent row P_n, n >= 1, is zero or real-rooted with coefficients of one sign","status":"proved"},"rows_compared":16,"schema":"polytool.recurrence-preserver-image.v1","statement":"proved: Q_n = lambda(n) T_n(P_(n+0)) with T = P((1) x + (1)) for every n >= 1, the side conditions hold for every n, and every parent row P_n, n >= 1, is zero or real-rooted with coefficients of one sign; so every Q_n, n >= 1, is zero or real-rooted with roots in (-inf, -1]"},"kind":"preserver_image"}